Answer:
11x+y=-28
Step-by-step explanation:
You stated "the equation". I am assuming that your instructor wants standard equation.
(-3, -5) and (2, 6)
The first thing we need to do is establish the slope of the line. Slope is defined as the change-of-y divided by the change-of-x...
(y-y1)/(x-x1)
(5, 6)/(-3-2)
(5+6)/(-3+2)
11/-1
-11
The standard format of an equation is...
Ax+By=C, neither A nor B equal zero and A is greater than zero.
slope=-A/B
slope=-(-11/1)
slope=11/1
11x+1y=C
11x+y=C
Let's plug-in one point to establish C...
(-3, 5) and (2, 6)
[11(-3)]+5=C
-33+5=-28
Let's verify with the other point...
[11(-2)]+6=C
-22-6=c
-28=c
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Answer:
11x+y=-28
Step-by-step explanation:
You stated "the equation". I am assuming that your instructor wants standard equation.
(-3, -5) and (2, 6)
The first thing we need to do is establish the slope of the line. Slope is defined as the change-of-y divided by the change-of-x...
(y-y1)/(x-x1)
(5, 6)/(-3-2)
(5+6)/(-3+2)
11/-1
-11
The standard format of an equation is...
Ax+By=C, neither A nor B equal zero and A is greater than zero.
slope=-A/B
slope=-(-11/1)
slope=11/1
11x+1y=C
11x+y=C
Let's plug-in one point to establish C...
(-3, 5) and (2, 6)
11x+y=C
[11(-3)]+5=C
-33+5=-28
Let's verify with the other point...
[11(-2)]+6=C
-22-6=c
-28=c