Answer:
What is the area of the shaded region? Use π=3.14
37.68 in² →Ans.
Explanation:
As you can see, the shaded area are we looking for. So solve the area of big circle tsaka mo iminus yung small circle.
Bigger Circle - Small Circle
⇒ πr² - πr²
where : Big Circle : R = 4 in
Small Circle : r = 2in
So, substitute r to the equation: Use π=3.14
⇒ Bigger Circle - Small Circle
⇒ (3.14)(4)² - (3.14)(2)²
⇒ 50.24-12.56
⇒ 37.68 in²
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Answer:
What is the area of the shaded region? Use π=3.14
37.68 in² →Ans.
Explanation:
As you can see, the shaded area are we looking for. So solve the area of big circle tsaka mo iminus yung small circle.
Bigger Circle - Small Circle
⇒ πr² - πr²
where : Big Circle : R = 4 in
Small Circle : r = 2in
So, substitute r to the equation: Use π=3.14
⇒ Bigger Circle - Small Circle
⇒ πr² - πr²
⇒ (3.14)(4)² - (3.14)(2)²
⇒ 50.24-12.56
⇒ 37.68 in²