(90+θ)
sin(90+θ)=cosθ
cos(90+θ)=−sinθ
tan(90+θ)=−cotθ
cosec(90+θ)=secθ
sec(90+θ)=−cosec θ
cot(90+θ)=−tanθ
(180−θ)
sin(180−θ)=sinθ
cos(180−θ)=−cosθ
tan(180−θ)=−tanθ
cosec (180−θ)=cosec θ
sec(180−θ)=−secθ
cot(180−θ)=−cotθ
(180+θ)
sin(180+θ)=−sinθ
cos(180+θ)=−cosθ
tan(180+θ)=tanθ
cosec (180+θ)=−cosec θ
sec(180+θ)=−secθ
cot(180+θ)=cotθ
hiii army how are you ?
do you remember me??
hope it helps you
pls mark me brainliest
Answer:
(a) The fulcrum in the centre, the load on one side and the effort on the other side make a lever of the first order.
(b) The load in the centre, the fulcrum on one side and the effort on the other side make a lever of the second order.
(c) The effort in the centre, the load on one side and the fulcrum on the other side make a lever of the third order.
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Verified answer
(90+θ)
sin(90+θ)=cosθ
cos(90+θ)=−sinθ
tan(90+θ)=−cotθ
cosec(90+θ)=secθ
sec(90+θ)=−cosec θ
cot(90+θ)=−tanθ
(180−θ)
sin(180−θ)=sinθ
cos(180−θ)=−cosθ
tan(180−θ)=−tanθ
cosec (180−θ)=cosec θ
sec(180−θ)=−secθ
cot(180−θ)=−cotθ
(180+θ)
sin(180+θ)=−sinθ
cos(180+θ)=−cosθ
tan(180+θ)=tanθ
cosec (180+θ)=−cosec θ
sec(180+θ)=−secθ
cot(180+θ)=cotθ
hiii army how are you ?
do you remember me??
hope it helps you
pls mark me brainliest
your bunny
Answer:
(a) The fulcrum in the centre, the load on one side and the effort on the other side make a lever of the first order.
(b) The load in the centre, the fulcrum on one side and the effort on the other side make a lever of the second order.
(c) The effort in the centre, the load on one side and the fulcrum on the other side make a lever of the third order.