The sum of this problem is [tex]\frac{17}{3}[/tex] or [tex]5\frac{2}{3}[/tex] .
Step-by-step explanation:
First, convert the whole number into a fraction. To make a whole number a fraction, just add a denominator of one to the whole number.
= [tex]\frac{2}{3} + 5[/tex]
[tex]\frac{2}{3} + \frac{5}{1}[/tex]
Second, multiply [tex]\frac{5}{1}[/tex] to the denominator of [tex]\frac{2}{3}[/tex]for them to have the same denominator.
= [tex]\frac{2}{3} + \frac{5}{1}[/tex]
[tex]\frac{5}{1}[/tex] x [tex]\frac{3}{3}[/tex]
[tex]\frac{15}{3}[/tex]
Third, add both fractions. Now that you have two fractions with the same denominator, add the numerators of the two fractions while maintaining the original denominator.
= [tex]\frac{2}{3} + \frac{15}{3}[/tex]
[tex]\frac{17}{3}[/tex]
To simplify the fraction, turn the improper fraction to a mixed fraction. Divide the numerator by the denominator, we will get 5 and the remainder of 2. The quotient will be the whole number while the remainder will be the numerator.
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Verified answer
Answer:
The sum of this problem is [tex]\frac{17}{3}[/tex] or [tex]5\frac{2}{3}[/tex] .
Step-by-step explanation:
First, convert the whole number into a fraction. To make a whole number a fraction, just add a denominator of one to the whole number.
= [tex]\frac{2}{3} + 5[/tex]
[tex]\frac{2}{3} + \frac{5}{1}[/tex]
Second, multiply [tex]\frac{5}{1}[/tex] to the denominator of [tex]\frac{2}{3}[/tex] for them to have the same denominator.
= [tex]\frac{2}{3} + \frac{5}{1}[/tex]
[tex]\frac{5}{1}[/tex] x [tex]\frac{3}{3}[/tex]
[tex]\frac{15}{3}[/tex]
Third, add both fractions. Now that you have two fractions with the same denominator, add the numerators of the two fractions while maintaining the original denominator.
= [tex]\frac{2}{3} + \frac{15}{3}[/tex]
[tex]\frac{17}{3}[/tex]
To simplify the fraction, turn the improper fraction to a mixed fraction. Divide the numerator by the denominator, we will get 5 and the remainder of 2. The quotient will be the whole number while the remainder will be the numerator.
= [tex]5\frac{2}{3}[/tex]