Answer:
The amount of CH₄ matter needed to produce 35 mol of water is: n= 17.5 moℓ.
Balanced equation that occurs
CH₄ + 2 O₂ → CO₂ + 2 H₂O
- by the stoichiometry of the chemical equation we see that 1 moℓ of CH₄ produces 2 moℓ of H₂O, thus:
Rule of three
[tex]\begin{gathered}1~mo\ell(CH_{4})---2~mo\ell(H_{2}O)\\ ~~~n-------~35~mo\ell (H_{2}O)\\ \\ n=\dfrac{1~mo\ell\times35~mo\ell}{2~mo\ell} \\ \\ \\ n=17.5~mo\ell \end{gathered}[/tex]
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Verified answer
Answer:
The amount of CH₄ matter needed to produce 35 mol of water is: n= 17.5 moℓ.
Balanced equation that occurs
CH₄ + 2 O₂ → CO₂ + 2 H₂O
- by the stoichiometry of the chemical equation we see that 1 moℓ of CH₄ produces 2 moℓ of H₂O, thus:
Rule of three
[tex]\begin{gathered}1~mo\ell(CH_{4})---2~mo\ell(H_{2}O)\\ ~~~n-------~35~mo\ell (H_{2}O)\\ \\ n=\dfrac{1~mo\ell\times35~mo\ell}{2~mo\ell} \\ \\ \\ n=17.5~mo\ell \end{gathered}[/tex]
#BrainlyEveryday