Answer:
9.8m/s
gm/r.r g formula
Acceleration of free fall is the acceleration produced on an object falling under the influence of gravitational force alone. It is denoted by g.
[tex]g = \frac{gm}{ {r}^{2} } .....{1}[/tex]
where G =
[tex]6.7 \times {10}^{ - 11} {nm}^{2} /kg²[/tex]
M =
[tex]6 \times {10}^{24} kg[/tex]
R =
[tex]6.4 \times {10}^{6} m[/tex]
Substituting the values in equation 1, we get:
g = 9.8 m/s²
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Answer:
9.8m/s
gm/r.r g formula
Verified answer
Answer:
Acceleration of free fall is the acceleration produced on an object falling under the influence of gravitational force alone. It is denoted by g.
Derivation
[tex]g = \frac{gm}{ {r}^{2} } .....{1}[/tex]
where G =
[tex]6.7 \times {10}^{ - 11} {nm}^{2} /kg²[/tex]
M =
[tex]6 \times {10}^{24} kg[/tex]
R =
[tex]6.4 \times {10}^{6} m[/tex]
Substituting the values in equation 1, we get:
g = 9.8 m/s²