Answer:
assume that the 5th term be the 1st term and the 11th term be the 6th term
lets find their common difference by using the arithmetic formula
an=a1+(n-1)d
a(6)=75+(6-1)d
177=75+5d
177-75=5d
102=5d
20.4=d
so 40-5=35
lets find the 35th term
a(35)=75+(35-1)(20.4)
a(35)=75+(34)(20.4)
a(35)=75+683.4
a(35)=785.4
then go back to the original terms
hence, the 40th term is 785.4
answer: 785.4
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Verified answer
Answer:
assume that the 5th term be the 1st term and the 11th term be the 6th term
lets find their common difference by using the arithmetic formula
an=a1+(n-1)d
a(6)=75+(6-1)d
177=75+5d
177-75=5d
102=5d
20.4=d
so 40-5=35
lets find the 35th term
a(35)=75+(35-1)(20.4)
a(35)=75+(34)(20.4)
a(35)=75+683.4
a(35)=785.4
then go back to the original terms
hence, the 40th term is 785.4
answer: 785.4