Answer:
Given : The root of a Quadratic equation kx² - 14x + 8 = 0 is 2
\begin{gathered} \\ \\ \end{gathered}
To find : Find the value of k
\begin{gathered} \\ \\ \qquad{\rule{200pt}{2pt}} \end{gathered}
SolutioN :
\maltese \; {\underline{\underline{\sf{ \; Calculating \; the \; value \; of \; k \; :- }}}}✠
Calculatingthevalueofk:−
\longmapsto⟼ The root of this equation is 2 .It means that if we will put the value of x as 2 we could get the answer as k .Let's Solve :
\begin{gathered} \; \; :\implies \; \; \sf { kx^2 - 14x + 8 = 0 } \\ \\ \end{gathered}
:⟹kx
2
−14x+8=0
\begin{gathered} \; \; :\implies \; \; \sf { k(2)^2 - 14(2) + 8 = 0 } \\ \\ \end{gathered}
:⟹k(2)
−14(2)+8=0
\begin{gathered} \; \; :\implies \; \; \sf { 4k - 14(2) + 8 = 0 } \\ \\ \end{gathered}
:⟹4k−14(2)+8=0
\begin{gathered} \; \; :\implies \; \; \sf { 4k - 28 + 8 = 0 } \\ \\ \end{gathered}
:⟹4k−28+8=0
\begin{gathered} \; \; :\implies \; \; \sf { 4k - 28 = 0 - 8 } \\ \\ \end{gathered}
:⟹4k−28=0−8
\begin{gathered} \; \; :\implies \; \; \sf { 4k = (- 8) + 28 } \\ \\ \end{gathered}
:⟹4k=(−8)+28
\begin{gathered} \; \; :\implies \; \; \sf { 4k = 20 } \\ \\ \end{gathered}
:⟹4k=20
\begin{gathered} \; \; :\implies \; \; \sf { k = \dfrac{20}{4} } \\ \\ \end{gathered}
:⟹k=
4
20
\begin{gathered} \; \; :\implies \; \; \sf { k = \cancel\dfrac{20}{4} } \\ \\ \end{gathered}
\begin{gathered} \; \; :\implies \; \; {\pmb{\underline{\boxed{\purple{\frak { k = 5 }}}}}} \; \bigstar \\ \\ \end{gathered}
:⟹
k=5
★
\qquad \; \therefore \;∴ Value of k is 5
\begin{gathered} \\ {\underline{\rule{300pt}{9pt}}} \end{gathered}
^-^
Explanation:
taekook forever
trust
sharing all thouts
some fights still trust ♀
care
etc.............. ♥
please mark as brilliant
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
Given : The root of a Quadratic equation kx² - 14x + 8 = 0 is 2
\begin{gathered} \\ \\ \end{gathered}
To find : Find the value of k
\begin{gathered} \\ \\ \qquad{\rule{200pt}{2pt}} \end{gathered}
SolutioN :
\maltese \; {\underline{\underline{\sf{ \; Calculating \; the \; value \; of \; k \; :- }}}}✠
Calculatingthevalueofk:−
\longmapsto⟼ The root of this equation is 2 .It means that if we will put the value of x as 2 we could get the answer as k .Let's Solve :
\begin{gathered} \; \; :\implies \; \; \sf { kx^2 - 14x + 8 = 0 } \\ \\ \end{gathered}
:⟹kx
2
−14x+8=0
\begin{gathered} \; \; :\implies \; \; \sf { k(2)^2 - 14(2) + 8 = 0 } \\ \\ \end{gathered}
:⟹k(2)
2
−14(2)+8=0
\begin{gathered} \; \; :\implies \; \; \sf { 4k - 14(2) + 8 = 0 } \\ \\ \end{gathered}
:⟹4k−14(2)+8=0
\begin{gathered} \; \; :\implies \; \; \sf { 4k - 28 + 8 = 0 } \\ \\ \end{gathered}
:⟹4k−28+8=0
\begin{gathered} \; \; :\implies \; \; \sf { 4k - 28 = 0 - 8 } \\ \\ \end{gathered}
:⟹4k−28=0−8
\begin{gathered} \; \; :\implies \; \; \sf { 4k = (- 8) + 28 } \\ \\ \end{gathered}
:⟹4k=(−8)+28
\begin{gathered} \; \; :\implies \; \; \sf { 4k = 20 } \\ \\ \end{gathered}
:⟹4k=20
\begin{gathered} \; \; :\implies \; \; \sf { k = \dfrac{20}{4} } \\ \\ \end{gathered}
:⟹k=
4
20
\begin{gathered} \; \; :\implies \; \; \sf { k = \cancel\dfrac{20}{4} } \\ \\ \end{gathered}
:⟹k=
4
20
\begin{gathered} \; \; :\implies \; \; {\pmb{\underline{\boxed{\purple{\frak { k = 5 }}}}}} \; \bigstar \\ \\ \end{gathered}
:⟹
k=5
k=5
★
\begin{gathered} \\ \\ \end{gathered}
\qquad \; \therefore \;∴ Value of k is 5
\begin{gathered} \\ {\underline{\rule{300pt}{9pt}}} \end{gathered}
^-^
Explanation:
taekook forever
Verified answer
Answer:
trust
sharing all thouts
some fights still trust ♀
care
etc.............. ♥
Explanation:
please mark as brilliant