Question: What are the two ordered pair in the equation, 3x - 3y =6?

Answer:

A. (0,-2), (1,-1)

B. (0,-1), (1, -2)

C. (0, -3), (1, -1)​

Solution:

A. (0,-2), (1,-1)

#(0,-2)#

→ 3x-3y=6

→ 3(0)-3(-2)=6

→ (0)+6=6

→ 6=6 (True)

#(1,-1)#

→ 3x-3y=6

→ 3(1)-3(-1)=6

→ (3)+(3)=6

→ 6=6 (True)

B. (0,-1), (1, -2)

#(0,-1)#

→ 3x-3y=6

→ 3(0)-3(-1)=6

→ 3+3=6

→ 6=6 (True)

#(1,-2)#

→ 3x-3y=6

→ 3(1)-3(-2)=6

→ 3+6=6

→ 9=6 (False)

C. (0, -3), (1, -1)​

#(0,-3)#

→ 3x-3y=6

→ 3(0)-3(-3)=6

→ (3)+9=6

→ 12=6 (False)

#(1,-1)#

→ 3x-3y=6

→ 3(1)-3(-1)=6

→ (3)+(3)=6

→ 6=6 (True)

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