Answer:
find the factors of 12 that can be added as -7
(x-4)(x-3) use foil method
x(x)= x²
x(-3)= -3x
x(-4)= -4x
(-4)(-3)= 12 multiplying same sign becomes positive same as dividing them
x-4=0 transfer 4, that becomes x= 4
x-3 transfer 3, that becomes x= 3
Step-by-step explanation:
factor x² + 7x + 12 using the AC method
(x+3) (x+4)=0
if any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0
x+3=0
x+4=0
Set the first factor equal to 0 and solve.
x= -3
Set the next factor equal to 0 and solve.
x= -4
The final solution is all the values that make. (x+3)(x+4)=0 true.
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Answer:
Factoring
find the factors of 12 that can be added as -7
(x-4)(x-3) use foil method
x(x)= x²
x(-3)= -3x
x(-4)= -4x
(-4)(-3)= 12 multiplying same sign becomes positive same as dividing them
Roots are x= 4 & x= 3
x-4=0 transfer 4, that becomes x= 4
x-3 transfer 3, that becomes x= 3
Step-by-step explanation:
factor x² + 7x + 12 using the AC method
(x+3) (x+4)=0
if any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0
x+3=0
x+4=0
Set the first factor equal to 0 and solve.
x= -3
Set the next factor equal to 0 and solve.
x= -4
The final solution is all the values that make. (x+3)(x+4)=0 true.