Answer:
The possible roots are:
Step-by-step explanation:
Given polynomial:
Constant, p: -6
Coefficient of leading term, q: 2
Factors of -6: ± (1, 2, 3, 6)
Factors of -2: ± (1, 2)
Possible roots, p/q ⇒ divide each factor of p by each factor of q.
(The question only requires possible roots. To solve for the roots of the cubic polynomial, use synthetic division.)
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Answers & Comments
Answer:
The possible roots are:
±1, ±1/2, ± 2, ±3/2, ±3, ±6
Step-by-step explanation:
Given polynomial:
2x³ + 3x² - 4x - 6 = 0
Constant, p: -6
Coefficient of leading term, q: 2
Factors of -6: ± (1, 2, 3, 6)
Factors of -2: ± (1, 2)
Possible roots, p/q ⇒ divide each factor of p by each factor of q.
p/q = ±1, ±1/2, ± 2, ±3/2, ±3, ±6
(The question only requires possible roots. To solve for the roots of the cubic polynomial, use synthetic division.)