Answer:
molar mass of CH4 = 16 g
Molar mass of O2 = 32 g
Let us assume that X g of each is present in the mixture.
Number of moles of CH4 = X /16
Number of moles of O2 = X/32
Total mole = X/16 + X/32 = 3X/32
mole fraction of O2 =X/32 ÷ 3X/32 =1/3
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Answer:
molar mass of CH4 = 16 g
Molar mass of O2 = 32 g
Let us assume that X g of each is present in the mixture.
Number of moles of CH4 = X /16
Number of moles of O2 = X/32
Total mole = X/16 + X/32 = 3X/32
mole fraction of O2 =X/32 ÷ 3X/32 =1/3