What are the factors of x2 - 64 ?
a. (x + 8) (x + 8)
b. (x + 16)(x-4)
c. (x-8)(X + 8)
d. (x + 32)(x + 2)
a. (x + 8) (x + 8)
b. (x + 16)(x-4)
c. (x-8)(X + 8)
d. (x + 32)(x + 2)
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Answer:
C
Step-by-step explanation:
Since both terms are perfect squares, factor using the difference of squares formula, a^2-b^2=(a+b)(a-b) where a=x and b=8
(x+8) (x+8)
I'm not quite sure of my answer sorry kung wrong