What are the factors of the polynomial 8r3 + 27?
a. (2r − 3)(4r2 + 6 + 9)
b. (2r + 3)(4r2 − 6 + 9)
c. (2r + 3)(4r2 + 6 + 9)
d. (2r − 3)(4r2 − 6 + 9)
(Note: next to "r" is exponents)
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a. (2r − 3)(4r2 + 6 + 9)
b. (2r + 3)(4r2 − 6 + 9)
c. (2r + 3)(4r2 + 6 + 9)
d. (2r − 3)(4r2 − 6 + 9)
(Note: next to "r" is exponents)
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Answer:
d. (2r - 3)(4r2 - 6 + 9)
Step-by-step explanation:
because the positive is equally negative
Answer:
b. (2r + 3) (4r2 - 6r +9)
Step-by-step explanation:
Using formula of "Sum of two cubes"