Answer:
(x+1)2+(y−5)2−(y−5)2=0−(y−5)2(x+1)2+(y−5)2−(y−5)2=0−(y−5)2
(x+1)2+0=0−(y−5)2(x+1)2+0=0−(y−5)2
(x+1)2=−(y−5)2⟶(x+1)2=−(y−5)2⟶ Equation EE
The square of any number is always non-negative. So, we have
(x+1)2≥0(x+1)2≥0
and
(y−5)2≥0(y−5)2≥0
So, the equation EE is valid if and only if
(x+1)2=0(x+1)2=0
(y−5)2=0(y−5)2=0
Solving the equations, we have
(x+1)2=0⟹x+1=0(x+1)2=0⟹x+1=0
⟹x=−1⟹x=−1
(y−5)2=0⟹y−5=0(y−5)2=0⟹y−5=0
⟹y=5⟹y=5
So, we have
x+y=y+x=5+(−1)=5−1=4x+y=y+x=5+(−1)=5−1=4
x+y=4x+y=4
Explanation:
I'm also fine
ummm,
1) make my Allah and parents proud of me
2) meet BTS
3) Go to concert
4) follow my dream whether someone supports me or not :(
5) I wanna be inspiration of someone like I mean I want to do something that everyone would admire me
6) I want to prepare myself for Akirah
7) become a billionaire
these are the things...
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Answers & Comments
Answer:
(x+1)2+(y−5)2−(y−5)2=0−(y−5)2(x+1)2+(y−5)2−(y−5)2=0−(y−5)2
(x+1)2+0=0−(y−5)2(x+1)2+0=0−(y−5)2
(x+1)2=−(y−5)2⟶(x+1)2=−(y−5)2⟶ Equation EE
The square of any number is always non-negative. So, we have
(x+1)2≥0(x+1)2≥0
and
(y−5)2≥0(y−5)2≥0
So, the equation EE is valid if and only if
(x+1)2=0(x+1)2=0
and
(y−5)2=0(y−5)2=0
Solving the equations, we have
(x+1)2=0⟹x+1=0(x+1)2=0⟹x+1=0
⟹x=−1⟹x=−1
and
(y−5)2=0⟹y−5=0(y−5)2=0⟹y−5=0
⟹y=5⟹y=5
So, we have
x+y=y+x=5+(−1)=5−1=4x+y=y+x=5+(−1)=5−1=4
x+y=4x+y=4
Explanation:
I'm also fine
Verified answer
Answer:
ummm,
1) make my Allah and parents proud of me
2) meet BTS
3) Go to concert
4) follow my dream whether someone supports me or not :(
5) I wanna be inspiration of someone like I mean I want to do something that everyone would admire me
6) I want to prepare myself for Akirah
7) become a billionaire
these are the things...