Given :-

• Water flows out through a circular pipe whose internal diameter is 2 cm. at the rate of 6 metres per second into a cylindrical tank.

• The radius of cylinderical tank is 60 cm.

To Find :-

• The rise in the level of water in 30 minutes?

Formula Used :-

Where,

• r = radius of cylinder

• h = height of cylinder

Solution :-

Given that,

• Diameter of cylindrical pipe, d = 2 cm

• Radius of cylindrical pipe, r = 1 cm

• Water flows from it at the rate of 6 m/ sec = 600 cm/sec

So,

☆ Volume of water flow in 1 second is

Now,

We know,

So,

Hence,

☆ Volume flow in 1800 seconds is

Now,

Let assume that

• The water level rise in tank in 1800 seconds be 'h' cm.

• Radius of cylindrical tank, R = 60 cm

According to statement,

More Information:

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = 4/3πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²