2. Two metallic conductors have net charges of 70PC & - 70 pC, which results in a potential difference of 20V b/w them. What is the capacitance of system?
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Explanation:
Charge= 70 pC=70*10¹² C
PD=20V
Capacitance= q/V=70*10¹²/20
=35*10¹²=35pF