f(x)=(x+1)(x+2)(x−4)
Explanation:
f(x) = x^3 - x^2 - 10x - 8.
We find out that
f(-1) = -1 -1 + 10 - 8 = 0,
then, one factor is (x + 1).
After division -->
f(x)=(x+1)(x2−2x−8)
The trinomial in parentheses can be factored.
Find 2 numbers knowing sum (-2) and product (-8).
They are (2) and (-4)
(x2−2x−8)=(x+2)(x−4)
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Answers & Comments
f(x)=(x+1)(x+2)(x−4)
Explanation:
f(x) = x^3 - x^2 - 10x - 8.
We find out that
f(-1) = -1 -1 + 10 - 8 = 0,
then, one factor is (x + 1).
After division -->
f(x)=(x+1)(x2−2x−8)
The trinomial in parentheses can be factored.
Find 2 numbers knowing sum (-2) and product (-8).
They are (2) and (-4)
(x2−2x−8)=(x+2)(x−4)
f(x)=(x+1)(x+2)(x−4)