vapour pressure of water at 20 °C is 17.5mm of Hg and lowering of vapour pressure of sugar solution is 0.061 mm of Hg .calculate 1.relative lowering of vapour pressure 2.vapour pressure of the solution 3. mole fraction of sugar and water
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Answer:
1. The relative lowering of vapour pressure = 0.003485
2. Vapour pressure of solution = 17.439 mm of Hg
3. Mole fraction of sugar = 0.003485
Mole fraction of water = 0.996515
1=0.0348
2=17.439
3=0.99652