Hey Mate,
The given quadratic equation is ;
3ax² - 6x + 1 = 0
Now , Comparing the given quadratic equation with the general quadratic equation Ax² + Bx + C = 0 , we have ;
A = 3a
B = -6
C = 1
Now The discriminant of the given quadratic equation will be given as ;
=> D = B² - 4AC
=> D = (-6)² - 4•3a•1
=> D = 36 - 12a
=> D = 12(3 - a)
=> 12a = 36
=> a = 3
Therefore, the quadratic equation is 9[tex]x^{2}[/tex]-6x+1 = 0
6 +0/18 , 6-0/18 = 1/3 and 1/3 Because D=0
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Answers & Comments
Hey Mate,
The given quadratic equation is ;
3ax² - 6x + 1 = 0
Now , Comparing the given quadratic equation with the general quadratic equation Ax² + Bx + C = 0 , we have ;
A = 3a
B = -6
C = 1
Now The discriminant of the given quadratic equation will be given as ;
=> D = B² - 4AC
=> D = (-6)² - 4•3a•1
=> D = 36 - 12a
=> D = 12(3 - a)
=> D = 36 - 12a
=> 12a = 36
=> a = 3
Therefore, the quadratic equation is 9[tex]x^{2}[/tex]-6x+1 = 0
6 +0/18 , 6-0/18 = 1/3 and 1/3 Because D=0