v 5x - 4 x square + 3 a t t1) 4 x square - 3 x -1 (2) 3 x square + 4 x -4 (3) 5x square + 12 x + 7 (4) t cube -2t squared -15t Choose the correct answer the syllable of has been promoted to a 'beat' position between two other unstressed syllables; this does not mean, though, that it should be heavily stressed in reading aloud. Where promotion occurs on the last syllable of an iambic line, it sometimes produces a weak ending.the syllable of has been promoted to a 'beat' position between two other unstressed syllables; this does not mean, though, that it should be heavily stressed in reading aloud. Where promotion occurs on the last syllable of an iambic line, it sometimes produces a weak ending.
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Verified answer
Answer:
Consider the given polynomial f(x)=5x
2
+12x+7
Find the zeros that
⇒5x
2
+12x+7=0
⇒5x
2
+(7+5)x+7=0
⇒5x
2
+7x+5x+7=0
⇒5x
2
+5x+7x+7=0
⇒5x(x+1)+7(x+1)=0
⇒(x+1)(5x+7)=0
⇒x+1=05x+7=0
⇒x=−1andx=−
5
7
Hence, this is the answer.
Verify the relation between the zeros and the coefficient.
We know that,
Sum of zeros=−
cofficentofx
2
cofficentofx
⇒−1+(−
5
7
)=−
5
12
⇒−
5
12
=−
5
12
Now, product of zeros=−
cofficentofx
2
constant
⇒−1×(−
5
7
)=
5
7
⇒
5
7
=
5
7
Hence, this the complete solution.
Step-by-step explanation:
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Answer:
Choose the correct answer the syllable of has been promoted to a 'beat' position between two other unstressed syllables; this does not mean, though, that it should be heavily stressed in reading aloud. Where promotion occurs on the last syllable of an iambic line, it sometimes produces a weak ending.the syllable of has been promoted to a 'beat' position between two other unstressed syllables; this does not mean, though, that it should be heavily stressed in reading aloud. Where promotion occurs on the last syllable of an iambic line, it sometimes produces a weak ending.
Step-by-step explanation:
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