Answer:
(5x)
[tex](5x) {}^{2} + (3y)^{2} - 2(5x)(3y) \\ = 25x {}^{2} + 9y {}^{2} - 30xy[/tex]
using (a-b)^2=a^2+b^2-2ab
[tex] \bf \green{= > {(5x - 3y)}^{2} }[/tex]
[tex] = 25 {x}^{2} + 9 {y}^{2} - 2(5x)(3y) \\ = > \color{cyan} \boxed{25 {x}^{2} + 9 {y}^{2} - 30xy}[/tex]
[tex] \underbrace{ \sf \color{magenta} {(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab}[/tex]
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Answer:
(5x)
[tex](5x) {}^{2} + (3y)^{2} - 2(5x)(3y) \\ = 25x {}^{2} + 9y {}^{2} - 30xy[/tex]
using (a-b)^2=a^2+b^2-2ab
Verified answer
Solution:-
[tex] \bf \green{= > {(5x - 3y)}^{2} }[/tex]
[tex] = 25 {x}^{2} + 9 {y}^{2} - 2(5x)(3y) \\ = > \color{cyan} \boxed{25 {x}^{2} + 9 {y}^{2} - 30xy}[/tex]
Identity:-
[tex] \underbrace{ \sf \color{magenta} {(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab}[/tex]