Answer:
Using Kirchhoff's voltage law in the above loop:
−20V+I
1
×20+I
×30=0
50I
=20+ I 1
50/ 20
= 5/ 2
=0.4A
HOPE IT IS HELPFUL...
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Answers & Comments
Answer:
Using Kirchhoff's voltage law in the above loop:
−20V+I
1
×20+I
1
×30=0
50I
1
=20+ I 1
50/ 20
= 5/ 2
=0.4A
HOPE IT IS HELPFUL...