3. Again with Q as centre, draw another arc of radius 2 cm. Then BM is a line which touches the two arcs. Then BM is a line parallel to PQ.
4. With Q as centre, draw an arc of radius 3.5 cm. With R as centre draw another arc of radius 3.5 cm. Draw a line HC which touches these two arcs. Let these two parallel line intersect at A.
Answers & Comments
Answer:
Let x be the number of boys in the school. Then, the number of girls in the school will be x + 50.
According to the question,
x + (x+50) = 1070
⇒
2
x
+
50
=
1070
⇒
2
x
=
1070
−
50
[
t
r
a
n
s
p
o
s
i
n
g
50
t
o
R
H
S
]
⇒
2
x
=
1020
⇒
x
=
510
[
d
i
v
i
d
i
n
g
b
o
t
h
s
i
d
e
s
b
y
2
]
So, the number of boys in the school = 510.
∴
Number of girls in the school = 510 + 50 = 560.
Verified answer
Answer:
1. Draw
PQR =
80°
2. With P as centre draw an arc of radius 2 cm.
3. Again with Q as centre, draw another arc of radius 2 cm. Then BM is a line which touches the two arcs. Then BM is a line parallel to PQ.
4. With Q as centre, draw an arc of radius 3.5 cm. With R as centre draw another arc of radius 3.5 cm. Draw a line HC which touches these two arcs. Let these two parallel line intersect at A.