Question:
A bag contains lemon flavored candies only. Malini takes out one candy without looking into the bag. What is the probability that she takes out
(i) an orange flavored candy?
(ii) a lemon flavored candy?
Solution:
(i) We know that the bag only contains lemon-flavored candies.
So, The no. of orange flavored candies = 0
∴ The probability of taking out orange flavored candies = 0/1 = 0
(ii) As there are only lemon flavored candies, P(lemon flavored candies) = 1 (or 100%)
Step-by-step explanation:
Let E be the event of taking out a candy from bag.
Solution(i):
The bag contains only lemon flavored candies, and nothing else.
There are no orange flavored candies in the bag. Hence there is no possibility of taking out an orange candy.
Therefore, the probability of taking out an orange flavored candy =0
Solution(ii):
Therefore (No.of favorable outcomes)=(Total no.of possible outcomes)
We know that, Probability of an event E, P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
P(E)=1
Therefore, the probability of taking out a lemon flavored candy =1
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Answers & Comments
Question:
A bag contains lemon flavored candies only. Malini takes out one candy without looking into the bag. What is the probability that she takes out
(i) an orange flavored candy?
(ii) a lemon flavored candy?
Solution:
(i) We know that the bag only contains lemon-flavored candies.
So, The no. of orange flavored candies = 0
∴ The probability of taking out orange flavored candies = 0/1 = 0
(ii) As there are only lemon flavored candies, P(lemon flavored candies) = 1 (or 100%)
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Step-by-step explanation:
Let E be the event of taking out a candy from bag.
Solution(i):
The bag contains only lemon flavored candies, and nothing else.
There are no orange flavored candies in the bag. Hence there is no possibility of taking out an orange candy.
Therefore, the probability of taking out an orange flavored candy =0
Solution(ii):
The bag contains only lemon flavored candies, and nothing else.
Therefore (No.of favorable outcomes)=(Total no.of possible outcomes)
We know that, Probability of an event E, P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
P(E)=1
Therefore, the probability of taking out a lemon flavored candy =1