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SOLUTION:

Step 1: List the given values.

To convert the temperature from degree Celsius to kelvin, add 273 to the temperature expressed in degree Celsius.

[tex]\begin{aligned} V_1 & = \text{9.6 L} \\ T_1 & = 88^{\circ}\text{C} = \text{361 K} \\ V_2 & = \text{3.4 L} \end{aligned}[/tex]

Step 2: Calculate the final temperature (in degree Celsius) by using Charles' law.

To convert the temperature from kelvin to degree Celsius, subtract 273 from the temperature expressed in kelvin

[tex]\begin{aligned} \frac{V_1}{T_1} & = \frac{V_2}{T_2} \\ T_2V_1 & = T_1V_2 \\ \frac{T_2V_1}{V_1} & = \frac{T_1V_2}{V_1} \\ T_2 & = \frac{T_1V_2}{V_1} \\ & = \frac{(\text{361 K})(\text{3.4 L})}{\text{9.6 L}} \\ & = \text{128 K} \\ & = \boxed{-145^{\circ}\text{C}} \end{aligned}[/tex]

Hence, the final temperature of the gas is -145°C.

[tex]\\[/tex]

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