Verified answer

Answer:

Father : 38 years

Step-by-step explanation:

Let the present age of father be x years and of daughter be y years.

Now according to the question

x + y = 48 -----> x = (48 - y)

and,    [tex]\frac{x-2}{y-2} = \frac{9}{2}[/tex]

(x-2) 2 = 9(y-2)

2x - 4 = 9y - 18

2(48 - y) -4 = 9y -18

96 - 2y -4 = 9y - 18

110 = 11 y

y = 10

x = 48 - y = 48 - 10 = 38

thus father is 38 years old and daughter is 10 years old

Answer:

Father : 38 years

Step-by-step explanation:

Let the present age of father be x years and of daughter be y years.

Now according to the question

x + y = 48 -----> x = (48 - y)

and, \frac{x-2}{y-2} = \frac{9}{2}

y−2

x−2

=

2

9

(x-2) 2 = 9(y-2)

2x - 4 = 9y - 18

2(48 - y) -4 = 9y -18

96 - 2y -4 = 9y - 18

110 = 11 y

y = 10

x = 48 - y = 48 - 10 = 38

thus father is 38 years old and daughter is 10 years old