Two vertical pole AB and CD stand apart on a horizontal surface . A bird sitting on the trip of the pole AB want to pick up a worm that is at point P and fly back to the trip of the pole CD what is the minimum possible distance that the bird can over during this process
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Answers & Comments
Answer:
30 cm
Step-by-step explanation:
As per seen from the figure
the shortest distance to covered by bird
=AP+PC
Find AP and PC
InΔABP
AP=√(12²+5²=√144+25
AP=√169=13 cm
in ΔCPD
CP=√15²+8²
=√225+64
=√289=17
So PC=17 cm
Thus the shortest distance to covered by bird
=AP+PC
=13+17
=30 cm
Answer:
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