Let the two trains meet after x hours. Then, 60x−50x=120⇒10x=120⇒x=12hrs

Distance AB = (Dist. covered by slower train) + (Dist. covered by faster train)

=[(50×12)+(60×12)]km

=600km+720km=1320km

[tex]Speed =120 \: km \: per \: hour \\ \\ (i) Time =36 \: minutes \\ \\ 60 \: minutes =1 \: hour \\ \\ 36 \: minutes= \: \frac{1}{36} \: hour \\ \\ = 0.6 \: hours \\ \\ Distance=speed×time \\ \\ = (120 \:  km \:  hr)×(0.6 \: hr) \\ \\ = 72 \: km[/tex]

[tex] \\ [/tex]

[tex]Speed =150 \: km \: per \: hour \\ \\ (i) Time =36 \: minutes \\ \\ 60 \: minutes =1 \: hour \\ \\ 36 \: minutes= \: \frac{1}{36} \: hour \\ \\ = 0.6 \: hours \\ \\ Distance=speed×time \\ \\ = (150 \:  km \:  hr)×(0.6 \: hr) \\ \\ = 90 \: km[/tex]