Two tankers contain 620 litres and 840 litres of diesel respectively. Find the maximum capacity of a container which can measure the diesel of both the tankers in exact number of times.
To find the maximum capacity of a container that can measure the diesel from both tankers in exact numbers of times, we need to find the greatest common divisor (GCD) of the volumes of the two tankers.
Given:
Tanker 1 volume = 620 litres
Tanker 2 volume = 840 litres
To find the GCD, we can use the Euclidean algorithm.
Step 1: Divide the larger volume by the smaller volume.
840 ÷ 620 = 1 remainder 220
Step 2: Divide the previous divisor (620) by the remainder (220).
620 ÷ 220 = 2 remainder 180
Step 3: Divide the previous divisor (220) by the remainder (180).
220 ÷ 180 = 1 remainder 40
Step 4: Divide the previous divisor (180) by the remainder (40).
180 ÷ 40 = 4 remainder 20
Step 5: Divide the previous divisor (40) by the remainder (20).
40 ÷ 20 = 2 remainder 0
Since we have reached a remainder of 0, the last non-zero remainder (20) is the GCD of 620 and 840.
Therefore, the maximum capacity of a container that can measure the diesel from both tankers in exact numbers of times is 20 litres.
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Answer:
To find the maximum capacity of a container that can measure the diesel from both tankers in exact numbers of times, we need to find the greatest common divisor (GCD) of the volumes of the two tankers.
Given:
Tanker 1 volume = 620 litres
Tanker 2 volume = 840 litres
To find the GCD, we can use the Euclidean algorithm.
Step 1: Divide the larger volume by the smaller volume.
840 ÷ 620 = 1 remainder 220
Step 2: Divide the previous divisor (620) by the remainder (220).
620 ÷ 220 = 2 remainder 180
Step 3: Divide the previous divisor (220) by the remainder (180).
220 ÷ 180 = 1 remainder 40
Step 4: Divide the previous divisor (180) by the remainder (40).
180 ÷ 40 = 4 remainder 20
Step 5: Divide the previous divisor (40) by the remainder (20).
40 ÷ 20 = 2 remainder 0
Since we have reached a remainder of 0, the last non-zero remainder (20) is the GCD of 620 and 840.
Therefore, the maximum capacity of a container that can measure the diesel from both tankers in exact numbers of times is 20 litres.