Answer:

Given that:

∠APB=60∘,∠CPD=30∘,AC=80m

To find:

The height of the pole=AB=CD=?

Solution:

Let AB and CD  be the two poles of equal height and P be the point on the road between the poles.

In △APB,

tan60∘=APAB

or, AP=AB×tan60∘1

or, AP=3AB                −−−−−−−(i)

In △PCD,

tan30∘=CPCD

or, CP=CD×tan30∘1

or, CP=3CD=3AB     ∵AB=CD           −−−−−−−(ii)

Adding eqn. (i) and eqn. (ii) we get,

AP+CP=3AB+AB3

or, AC=AB(

Verified answer

Answer:

If two poles of equal heights are standing opposite each other on either side of the road, which is 80 m wide, and from a point between them on the road, the angles of elevation of the top of the poles are 60° and 30° respectively, then the height of the poles are 20√3 m and the distances of the point from the poles is ..