To show that triangles ABC and DBC are isosceles triangles with the same base BC, we need to prove that the two sides AB and AC of triangle ABC are equal in length, and the two sides DB and DC of triangle DBC are also equal in length.
Using the fact that both triangles share the base BC, we can start by proving that AB = AC. Then, we can prove that DB = DC.
Let's start with triangle ABC:
Since ABC is an isosceles triangle, we know that AB = AC. This is because the two sides adjacent to the base BC are equal in an isosceles triangle.
Now, let's move on to triangle DBC:
Since DBC is also an isosceles triangle, we can conclude that DB = DC. This is because the two sides adjacent to the base BC are equal.
Therefore, we have shown that both triangles ABC and DBC are isosceles triangles with the same base BC.
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Answer:
To show that triangles ABC and DBC are isosceles triangles with the same base BC, we need to prove that the two sides AB and AC of triangle ABC are equal in length, and the two sides DB and DC of triangle DBC are also equal in length.
Using the fact that both triangles share the base BC, we can start by proving that AB = AC. Then, we can prove that DB = DC.
Let's start with triangle ABC:
Since ABC is an isosceles triangle, we know that AB = AC. This is because the two sides adjacent to the base BC are equal in an isosceles triangle.
Now, let's move on to triangle DBC:
Since DBC is also an isosceles triangle, we can conclude that DB = DC. This is because the two sides adjacent to the base BC are equal.
Therefore, we have shown that both triangles ABC and DBC are isosceles triangles with the same base BC.