Two identical square mods of metal are welded end to end
as shown in figure (a) 20 calories of heat lows through it
in 4 minutes. If the rods are welded as shown in the same
amount of heat will flow through the rods in-
0°C
0°C
- 100°C
(a)
(a) Iminutes
(c) 4 minutes
(b) 2 minutes
(d) 16 minutes
as shown in figure (a) 20 calories of heat lows through it
in 4 minutes. If the rods are welded as shown in the same
amount of heat will flow through the rods in-
0°C
0°C
- 100°C
(a)
(a) Iminutes
(c) 4 minutes
(b) 2 minutes
(d) 16 minutes
Add an Answer
More Questions From This User See All
Answers & Comments
Answer:
The rate at which the heat is developed is given by
d t
d Q
=
L
KAδT
d t
d Q
=
2x
KAδ(T
1
−T
2
)
=5
Now , we have
d t
d Q
=
x
2KAδT
Therefore by solving above we have , t=2 minutes
So (b) 2 minutes is your answer !!
Explanation:
Hi !!
Hope it helps you !!
The rate at which the heat is developed is given by
dt
dQ
=
L
KAδT
dt
dQ
=
2x
KAδ(T
1
−T
2
)
=5
Now , we have
dt
dQ
=
x
2KAδT
Therefore by solving above we have , t=2 minutes
I hope it's help you