Answer:

When two different dice are thrown, the total number of outcomes is 36 and all the out-comes are equally likely. <br> (i) The outcomes favourable to the event 'sum of two number is 9' are (6, 3), (5, 4), (4, 5) and (3, 6) these are 4 in number. <br>

. <br> (ii) The outcomes favourable to the event 'sum of two numbers is 10' are (6, 4), (5, 5) and ( 4, 6). These are 3 in number. <br>

<br> (iii) The sum of at least 10 mean that sum is 10, 11 or 12. Therefore, the outcomes favourable to the event 'sum of at least 10' are (6, 4), (5, 5), (4, 6), (6, 5), (5, 6) and ( 6, 6). These are 6 in number. <br>

<br> (iv) As the sum of two number appearing on the top of two dice can never be 13, there is no outcomes favourable to the event 'sum of two numbers is 13'. <br>

<br> (v) As the sum of two numbers appearing on the top of two dice is always less than or equal to 12, all the 36 outcomes are favourable to the event 'sum is less than or equal to 12'. <br>

<br> (vi) The outcomes favourable to the event 'a multiple of 2 on one die and a multiple of 3 on the other die' are (2, 3), (2, 6), (4, 3), (4, 6), (6, 3) (6, 6), (3, 2), (3, 4), (3, 6), (6, 2) and (6, 4). <br>

The number of outcomes favourable to the given event = 11. <br

hope this answer will help you

plz mark me as brainlist