Answer:

1/6

Step-by-step explanation:

Given that Two dice are thrown.

So, Total number of possible outcomes, n(s) = 36.

(i) Getting a total of less than 5:

Let A be the event of getting the sum of two numbers is less than 5.

n(A) = (1,1),(1,2),(1,3),(2,1),(2,2),(3,1)

      = 6.

Required probability P(A) = n(A)/n(S)

                                          = 6/36

                                          = 1/6.

Hope it helps!

Answer: 1/6

Step-by-step explanation:

Given that Two dice are thrown

So, Total number of possible outcomes

n(s) = 36

Getting a total of less than 5

Let A be the event of getting the sum of two numbers is less than 5

n(A) = (1,1),(1,2),(1,3),(2,1),(2,2),(3,1) = 6 outcomes

Required probability P(A) = n(A)/n(S)

                                          = 6/36

                                          = 1/6