Two crossroads, each with width 7 m run at right angles through the centre of a square park of sides 105 m and parallel to its sides. Find the area of the roads. Also, find the cost of constructing the roads at the rate of ₹75 per m².
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Answers & Comments
Answer:
constructing the roads at the rate of Rs.105 per m
2
.
Easy
Solution
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width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(350+225)−25
=575−25
=550sqm
cost of the construction per sq.m =Rs.105
total cost =550×105=Rs 57750
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Step-by-step explanation:
Given :
Area of first road 7×105=735 sq.m
=735 ×75
=55125sqm