Two crossroads, each of width 4 m, runs at right angles through the centre of a rectangular park of length 70 m and breadth 45 m and parallel to the sides of the rectangle. Find the area of the road.
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Answer:
width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
cost of the construction per sq.m =Rs.105
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Step-by-step explanation:
width =4 m
length of first parallel road 70 m
area of first road 70×4=280 sq.m
length of second road=45 m
area of second road =45×4=180 sq.m
area of the common part of cross road with 4 m width that lies at the
center of the park 4×4 = 16 sq.m
area of roads = area of first road +area of second cross road−common area
=(280+180)−16
=460−16
=444 sqm