two chords of a circle of length 5cm and 11cm are parallel to each other to the opposite side of the centre. the distance between both the chords is 6cm. find the radius of the circle.
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AB=5cm. (given)
CD=11m. (given)
EF=6cm (given)
EC and ED are radius.
CF=FD=5.5cm. (by construction)
So in Δ ECF,
EF²+CF²=EC² (by phthogoras theorm)
=> 6²+5.5²=EC²
=> EC²=6²+5.5²
=> EC²= 66.25
=> EC= √66.25
=> EC= 8.1394103cm
As we know EC is radius and it is 8.1394103cm, so radius is 8.1394103cm.
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