Answer:

The electric potential at point B due to a point charge Q can be calculated by the formula:

V = kQ/r

where k is the Coulomb constant (9 x 10^9 N m^2/C^2) Q is the charge, and r is the distance from the charge to the point B

First, let's calculate the electric potential at point B due to Q1:

V1 = kQ1/r1 = (9 x 10^9 N m^2/C^2) x (2.8 x 10^-9 C)/(0.011 m) = 254.545 V

Note that we use the magnitude of the charge since we are only interested in the electric potential, not the direction.

Next, let's calculate the electric potential at point B due to Q2:

V2 = kQ2/r2 = (9 x 10^9 N m^2/C^2) x (2.8 x 10^-9 C)/(0.011 m) = -254.545 V

Note that the negative sign indicates that the electric potential due to Q2 is in the opposite direction to that of Q1.

The total electric potential at point B is the sum of V1 and V2:

V = V1 + V2 = 254.545 V - 254.545 V = 0 V

Therefore, the answer is not given in the options provided.