30.7 m

Step-by-step explanation:

height of first building (smaller)

= 10 m(given)

height of 2nd building (longer)

=( 10 + x )

width (horizontal distance between 2 buildings)

= 12m (given )

tan 60° = p/b = x / 12

√3= x /12 => x = 12√3 m

height of 2nd building= 10+12√3

= 10+ 12× 1.732 = 30.7 m

Hey mate,

30 . 78 metre

Let AB be small building and CD be small building .

.•. ED = BA = 10 m

Let CE = x

In △BCE

CE

Tan 60 = ––

BE

CE

----

===> √3 = 12

===> CE = 12 √3

Hence, CD = CE + ED

CD = 20 . 78 + 10

CD = 30 . 78

Thus, height of the second building will be

30.78 m

Hope it helps..