Two bodies are thrown vertically update with their initial speeds in ratio 2:3.Thee ratio of maximum heights reached by them and thr ratio of their time taken by them to return back to ground respectively are.
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Explanation:
Initial velocity u = g×t = 9.8×6 = 58.8 m/s
distance S1 travelled in first second is calculated using " S = u×t - (1/2)×g×t2 ", using u = 58.8 m/s, and t = 1 s;
S1 = 58.8×1 -(1/2)×9.8×1×= 53.9 m
Since the paticle reaches maximum height in 6 s, at 7th second travel, its initial velocity is zero.
hence distance S7 travelled in 7th second = (1/2)×9.8×1×1 = 4.9 m
hence the ratio S1 / S7 = 53.9 / 4.9 = 11