Answer:

the largest possible amount of each cheque will be 1215.

Step-by-step explanation:

Largest possible amount of cheque will be the HCF(6075,8505).

Applying Euclid's division lemma to 8505 and 6075, we have 8505=6075×1+2430

Since, remainder 2430



=0 again applying division lemma to 6075 and 2430

6075=2430×2+1215

Again remainder 1215



=0

So, again applying the division lemma to 2430 and 1215

2430=1215×2+0

Here the remainder is zero

So, HCF=1215

Therefore, the largest possible amount of each cheque will be 1215.

Answer:

The largest cheques of same amount will be 2430