Answer:

[tex]\boxed{\bf\:a = 60 \: } \\ [/tex]

Step-by-step explanation:

Given that,

Two parallel lines are intersected by a transversal and pair of alternate interior angles are (a + 10)° and (2a - 50)°.

We know,

If two parallel lines are intersected by a transversal, then pair of alternate interior angles are equal.

So, Using this property of parallel lines, we get

[tex]\sf\: a + 10 = 2a - 50 \\ [/tex]

[tex]\sf\: a - 2a = - 10 - 50 \\ [/tex]

[tex]\sf\: - a = - 60 \\ [/tex]

[tex]\implies\sf\:a = 60 \\ [/tex]

Hence,

Two parallel lines are intersected by a transversal and pair of alternate interior angles are (a + 10)° and (2a - 50)°, then a = 60

Answer:

a=

Step-by-step explanation:

Given that,

Two parallel lines are intersected by a transversal and pair of alternate interior angles are (a + 10)° and (2a - 50)°.

We know,

If two parallel lines are intersected by a transversal, then pair of alternate interior angles are equal.

So, Using this property of parallel lines, we get

\begin{gathered}\sf\: a + 10 = 2a - 50 \\ \end{gathered}

a+10=2a−50

\begin{gathered}\sf\: a - 2a = - 10 - 50 \\ \end{gathered}

a−2a=−10−50

\begin{gathered}\sf\: - a = - 60 \\ \end{gathered}

−a=−60

60

\begin{gathered}\implies\sf\:a = 60 \\ \end{gathered}

⟹a=60

Hence,

Two parallel lines are intersected by a transversal and pair of alternate interior angles are (a + 10)° and (2a - 50)°, then a = 60