1. In ∆ABC and ∆BAD,

AB = AB (common)

AC = BD (Given)

BC = AD (Given)

So, ∆ABC = ∆BAD by SSS congruency.

2. Yes, angle A = angle B by CPCT

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Step-by-step explanation:

[tex] \frac{ad}{db} = \frac{ae}{ec} [/tex]

we are given a triangle ABC in which a line parallel to side BC intersect other two sides ab and AC and DC and ac respectively we need to prove that.

letters join B and CD and then draw a perpendicular AC and EN perpendicular AB .

now area of triangle ADE equal to one half base into height equal to one half AD into EN

AREA ∆ ADE

[tex] = \frac{1}{2} ad \times en[/tex]

AREA ∆