Answer:
hi friend, let d/2 be the distance covered by train with a speed of 30kmph in t1 hours
→t1=d/60
it covers d/2 distance with a speed of 45km/h in t2 hours
→t2=d/90
average speed = total distance/total time
=d/(t1+t2)
=1/(1/60+1/90)
=1/(3+2)/180
=180/5=36kmph
I hope this will help u ;)
Average speed =
=Total distance/ total time =
= 2s/{t₁ +t₂} =
= 2s/{s/v₁) +(s/v₂)} =
=2v₁v₂/(v₁+v₂) =
=2•30•45/(30+45) = 36 km/h
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Verified answer
Answer:
hi friend, let d/2 be the distance covered by train with a speed of 30kmph in t1 hours
→t1=d/60
it covers d/2 distance with a speed of 45km/h in t2 hours
→t2=d/90
average speed = total distance/total time
=d/(t1+t2)
=1/(1/60+1/90)
=1/(3+2)/180
=180/5=36kmph
I hope this will help u ;)
Answer:
Average speed =
=Total distance/ total time =
= 2s/{t₁ +t₂} =
= 2s/{s/v₁) +(s/v₂)} =
=2v₁v₂/(v₁+v₂) =
=2•30•45/(30+45) = 36 km/h