Answer:
The central iodine atom in IF
7
undergoes sp
3
d
hybridization which results in pentagonal bipyramidal geometry.
Each axial F atom forms five 90
o
angles with five equatorial F atoms.
Hence, the total number of ∠FIF angles in IF
having the bond angle value of 90
is 10
is 10.
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Answer:
The central iodine atom in IF
7
undergoes sp
3
d
3
hybridization which results in pentagonal bipyramidal geometry.
Each axial F atom forms five 90
o
angles with five equatorial F atoms.
Hence, the total number of ∠FIF angles in IF
7
having the bond angle value of 90
o
is 10
Answer:
The central iodine atom in IF
7
undergoes sp
3
d
3
hybridization which results in pentagonal bipyramidal geometry.
Each axial F atom forms five 90
o
angles with five equatorial F atoms.
Hence, the total number of ∠FIF angles in IF
7
having the bond angle value of 90
o
is 10.