The current through the galvanometer, at the balanced condition of the bridge, is zero, which is IG = 0. Current through arms AB and BC is denoted by I1 Current through arms of AD as well as DC is I2 As per the circuital law of Kirchhoff, voltage drop through the closed-loop is 0.
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Explanation:
The current through the galvanometer, at the balanced condition of the bridge, is zero, which is IG = 0. Current through arms AB and BC is denoted by I1 Current through arms of AD as well as DC is I2 As per the circuital law of Kirchhoff, voltage drop through the closed-loop is 0.