Three resistors of 6 Ω, 3 Ω and 2 Ω are connected together so that the total resistance is greater than 6 Ω but less than 8 Ω. Draw a diagram to show this arrangement and calculate its total resistance.
SOLVE WITH WORKING
Please solve fast
NO SPAM
SOLVE WITH WORKING
Please solve fast
NO SPAM
Add an Answer
More Questions From This User See All
Answers & Comments
Explanation:
We connect the resistance of 3Ω and 2Ω in parallel to each other and then connect this (parallel combination) to the 6Ω resistance in series. The required arrangement is as shown in figure. The equivalent resistance of 3Ω and 2Ω in parallel.
1/R = 1/3 + 1/2 = 2 + 3/6 = 5/6
Or R = 6/5Ω = 1.2Ω.
Thus, the total resistance of the set up is (1.2 + 6)Ω = 7.2Ω