Since we know that the, current flowing in a series is same in throughout the circuit.
So we will find the equivalent resistance in the circuit and then by using the ohm's la, we can find the current passing through the circuit.
⠀⠀⠀⠀⠀⠀⠀⠀⠀R₁ + R₂ + R₃ + ... + Rₙ = R'⠀
[Where : R' = Equivalent resistance in the series circuit, R = Resistance in the resistors]
⠀⠀⠀⠀⠀⠀⠀⠀⠀V = IR⠀
[Where : V = Potential difference, I = Current, R = Resistance]
First let us find the equivalent resistance in the circuit.
⠀By using the formula for total resistance in a series circuit and substituting the values in it, we get :
⠀⠀=> R₁ + R₂ + R₃ = R'
⠀⠀=> 5 + 10 + 15 = R'
⠀⠀=> 30 = R'
⠀⠀⠀⠀⠀∴ R' = 30 Ω
Hence the equivalent resistance in the circuit is 30 Ω.
Now let us find the current in the circuit.
⠀By using the ohm's law and Substituting the value in it, we get :
⠀⠀=> V = IR
⠀⠀=> 15 = I × 30
⠀⠀=> 15/30 = I
⠀⠀=> 0.5 = l
⠀⠀⠀⠀⠀∴ I = 0.5 A
Therefore,
Answer:
Explanation:
Given,
Resistance in the resistor, R₁ = 5 Ω
Resistance in the resistor, R₂ = 10 Ω
Resistance in the resistor, R₃ = 15 Ω
Voltage, V = 15 V
To Find,
Current passing through the circuit.
Formula to be used,
Total Resistance, R' = R₁ + R₂ + R₃
Ohm's Law, V = IR
Solution,
Putting all the values, we get
At 1st here we have to find the equivalent resistance,
R' = R₁ + R₂ + R₃
⇒ R' = 5 + 10 + 15
⇒ R' = 30 Ω
Now, current passing through the circuit ,
V = IR
⇒ 15 = I × 30
⇒ 15/30 = I
⇒ 0.5 A = l
Hence, the current passing through the circuit is 0.5 A.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Answer :
Explanation :
Given :
To find :
Knowledge required :
Since we know that the, current flowing in a series is same in throughout the circuit.
So we will find the equivalent resistance in the circuit and then by using the ohm's la, we can find the current passing through the circuit.
⠀⠀⠀⠀⠀⠀⠀⠀⠀R₁ + R₂ + R₃ + ... + Rₙ = R'⠀
[Where : R' = Equivalent resistance in the series circuit, R = Resistance in the resistors]
⠀⠀⠀⠀⠀⠀⠀⠀⠀V = IR⠀
[Where : V = Potential difference, I = Current, R = Resistance]
Solution :
First let us find the equivalent resistance in the circuit.
⠀By using the formula for total resistance in a series circuit and substituting the values in it, we get :
⠀⠀=> R₁ + R₂ + R₃ = R'
⠀⠀=> 5 + 10 + 15 = R'
⠀⠀=> 30 = R'
⠀⠀⠀⠀⠀∴ R' = 30 Ω
Hence the equivalent resistance in the circuit is 30 Ω.
Now let us find the current in the circuit.
⠀By using the ohm's law and Substituting the value in it, we get :
⠀⠀=> V = IR
⠀⠀=> 15 = I × 30
⠀⠀=> 15/30 = I
⠀⠀=> 0.5 = l
⠀⠀⠀⠀⠀∴ I = 0.5 A
Therefore,
Verified answer
Answer:
Explanation:
Given,
Resistance in the resistor, R₁ = 5 Ω
Resistance in the resistor, R₂ = 10 Ω
Resistance in the resistor, R₃ = 15 Ω
Voltage, V = 15 V
To Find,
Current passing through the circuit.
Formula to be used,
Total Resistance, R' = R₁ + R₂ + R₃
Ohm's Law, V = IR
Solution,
Putting all the values, we get
At 1st here we have to find the equivalent resistance,
R' = R₁ + R₂ + R₃
⇒ R' = 5 + 10 + 15
⇒ R' = 30 Ω
Now, current passing through the circuit ,
V = IR
⇒ 15 = I × 30
⇒ 15/30 = I
⇒ 0.5 A = l
Hence, the current passing through the circuit is 0.5 A.