Three non-zero distict digit xyz are rearrange to the from three number xyz,yzx,zxy.If x+y+z =16 what is the remainder we get them sum is divided by 156
please give me right answer
please give me right answer
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Step-by-step explanation:
Given:--
XYZ is a three-digit number
XYZ is a three-digit numberWhere (X + Y + Z) is not a multiple of 3
Calculation:
Calculation:The general form of XYZ = 100X + 10Y + Z.
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + X
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z⇒ XYZ + YZX + ZXY = 111(X + Y + Z).
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z⇒ XYZ + YZX + ZXY = 111(X + Y + Z).Now, it is clear that 111 is the common factor.
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z⇒ XYZ + YZX + ZXY = 111(X + Y + Z).Now, it is clear that 111 is the common factor.So, XYZ + YZX + ZXY is divisible by 111 and it's factors
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z⇒ XYZ + YZX + ZXY = 111(X + Y + Z).Now, it is clear that 111 is the common factor.So, XYZ + YZX + ZXY is divisible by 111 and it's factorsFactors of 111 are 3 and 37. That eliminate option 3 and 37
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z⇒ XYZ + YZX + ZXY = 111(X + Y + Z).Now, it is clear that 111 is the common factor.So, XYZ + YZX + ZXY is divisible by 111 and it's factorsFactors of 111 are 3 and 37. That eliminate option 3 and 37But it is given that (X + Y+ Z) is not multiple of 3
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z⇒ XYZ + YZX + ZXY = 111(X + Y + Z).Now, it is clear that 111 is the common factor.So, XYZ + YZX + ZXY is divisible by 111 and it's factorsFactors of 111 are 3 and 37. That eliminate option 3 and 37But it is given that (X + Y+ Z) is not multiple of 3⇒ (XYZ + YZX + ZXY) is not divisible by 9.
Calculation:The general form of XYZ = 100X + 10Y + Z.The general form of YZX = 100Y + 10Z + XThe general form of ZXY = 100Z + 10X + Y.Using above, add the three numbers, we get ;⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z⇒ XYZ + YZX + ZXY = 111(X + Y + Z).Now, it is clear that 111 is the common factor.So, XYZ + YZX + ZXY is divisible by 111 and it's factorsFactors of 111 are 3 and 37. That eliminate option 3 and 37But it is given that (X + Y+ Z) is not multiple of 3⇒ (XYZ + YZX + ZXY) is not divisible by 9.⇒ (XYZ + YZX + ZXY) is not divisible by 9.